Elektron bermassa 9,0 x 10-31 kilogram bergerak dengan kecepatan 2,2 x 107 ms-1(Tetapan Planck = 6,6 x 10-34 Js) memiliki panjang gelombang de Broglie sebesar….
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Diketahui : m = 9.10⁻³¹ kg
v = 2,2.10⁷ m/s
h = 6,6.10⁻³⁴ Js
Ditanya : λ =.......?
Jawab : λ = h / mc
[tex] = \frac{6.6 \times 10 {}^{ - 34} }{2.2 \times 10 {}^{7} \times 9 \times 10 {}^{ - 31} } \\ = \frac{1}{27} \times 10 {}^{ - 10} \\ = \frac{ \frac{1}{27} }{10 {}^{10} } = \frac{10 {}^{10} }{27} \: m \: [/tex]
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